High School

There was an outbreak of illness caused by the bacteria called E. coli. As of June 15 of that year, 2,631 people had become sick, and 70 had died. What percentage of those who got sick also died? Round to the nearest tenth of a percent.

Answer :

The percentage of those who got sick and also died is 2.7%, rounded to the nearest tenth of a percent.

To calculate the percentage of those who got sick and also died due to the E. coli outbreak, you can use the following formula:

Percentage = (Number of deaths / Number of people who got sick) x 100

In this case, there were 70 deaths, and 2,631 people got sick. Plug these values into the formula:

Percentage = (70 / 2,631) x 100 = 2.7%

So, approximately 2.7% of those who became ill as a result of the E. coli outbreak also tragically lost their lives. Rounding to the nearest tenth of a percent, the percentage of fatalities among those who got sick is 2.7%. This calculation helps in understanding the severity and impact of the outbreak on the affected population.

To learn more about E. coli outbreak here

https://brainly.com/question/32902484

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