Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that:

[tex]
\[
\begin{array}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{\text{of the offspring will be heterozygous.}} \\
\hline
& W & w \\
\hline
W & Ww & Ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is:

[tex]
\[
\begin{array}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{} \\
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure, let's break this down step-by-step.

### First Cross: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)

1. Parent Genotypes:
- Male: Ww
- Female: ww

2. Determine Possible Offspring Genotypes:
- Using a Punnett square, you match each allele from the male with each allele from the female.

```
| w | w |
--------------
W | Ww | Ww |
w | ww | ww |
```

3. Results of the Punnett Square:
- There are two possible offspring genotypes from this cross: Ww and ww.
- Ww appears in two out of the four squares.
- Therefore, 50% of the offspring will be heterozygous (Ww).

### Second Cross: Heterozygous (Ww) and Homozygous Dominant (WW)

1. Parent Genotypes:
- Parent 1: Ww
- Parent 2: WW

2. Determine Possible Offspring Genotypes:
- Again, use a Punnett square to find the combination of alleles from each parent.

```
| W | W |
--------------
W | WW | WW |
w | Ww | Ww |
```

3. Results of the Punnett Square:
- Possible genotypes from this cross are WW or Ww.
- None of the offspring will be homozygous recessive (ww) since neither parent provides a recessive allele to form a homozygous recessive genotype.

So, summarizing the answers:
- In the first cross, 50% of the offspring will be heterozygous (Ww).
- In the second cross, there is a 0% probability of having a homozygous recessive (ww) offspring.