College

For questions 1-12, use partial quotients to divide. You may use counters or draw pictures to help.

1. [tex]4 \longdiv 92[/tex]

2. [tex]2 \longdiv 36[/tex]

3. [tex]5 \longdiv 75[/tex]

4. [tex]3 \longdiv 7[/tex]

Answer :

Let's go through the division problems step-by-step using partial quotients:

1. Dividing 92 by 4

- Start with 92 and determine how many times 4 can be subtracted.
- 92 divided by 4 gives us a quotient of 23.
- 92 minus 92 (4 times 23) is 0, so there is no remainder.

[tex]\[
\text{Quotient: } 23, \text{ Remainder: } 0
\][/tex]

2. Dividing 36 by 2

- Start with 36 and determine how many times 2 can be subtracted.
- 36 divided by 2 gives us a quotient of 18.
- 36 minus 36 (2 times 18) is 0, so there is no remainder.

[tex]\[
\text{Quotient: } 18, \text{ Remainder: } 0
\][/tex]

3. Dividing 75 by 5

- Start with 75 and determine how many times 5 can be subtracted.
- 75 divided by 5 gives us a quotient of 15.
- 75 minus 75 (5 times 15) is 0, so there is no remainder.

[tex]\[
\text{Quotient: } 15, \text{ Remainder: } 0
\][/tex]

4. Dividing 7 by 3

- Start with 7 and determine how many times 3 can be subtracted.
- 7 divided by 3 gives us a quotient of 2.
- 6 (3 times 2) is subtracted from 7, resulting in a remainder of 1.

[tex]\[
\text{Quotient: } 2, \text{ Remainder: } 1
\][/tex]

These steps give us the results for each division using partial quotients.