Answer :
Final answer:
The question is about understanding Hardy-Weinberg equilibrium and how it is used to determine whether a population is evolving or not, by comparing expected genotype frequencies to observed frequencies. Based on Hardy-Weinberg equilibrium calculations, it can be determined whether the given wolf population is in equilibrium or not.
Explanation:
To determine which statements are correct, we need to calculate the frequency of each allele (FB and FW) in the population. The number of FBFB genotype is 40 and the number of FWFW genotype is 220. The genotype FBFW is heterozygous, meaning it contains one of each allele, so its count should be split between the two: 20 to each. By adding these, we determine the frequency of each allele.
Now, we use these frequencies in the Hardy-Weinberg equilibrium equation to calculate the expected number of individuals with each genotype. If the calculated numbers correspond to the actual numbers of individuals with each genotype, the population is in Hardy-Weinberg equilibrium and is not evolving. If they do not match, the population is not in Hardy-Weinberg equilibrium, indicating it is evolving.
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The allele frequency represents how a population's genetic diversity is distributed. The precise assessment of genetic variation in a population is.
The percentage of people who have a particular genotype is known as genotype frequency, while the percentage of people who have a particular phenotype is known as phenotypic frequency.
Which statements accurately describe the population of wolves?
Add the predicted frequency of each genotype to the total population size to estimate the number of people carrying each genotype.
0.04 x 300 = 12 FBFB people
0.64300=192 FWFW people and 0.32300=96 FBFW people.
The fact that the expected number of individuals with each genotype, as determined by the Hardy-Weinberg equation, does not match the actual number of individuals with each genotype suggests that the wolf population may be changing.
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